HACCKERANK LOOP 1

 A for loop is a programming language statement which allows code to be repeatedly executed.

The syntax is

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>

• expression_1 is used for intializing variables which are generally used for controlling the terminating flag for the loop.
• expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
• expression_3 is generally used to update the flags/variables.

A sample loop is

for(int i = 0; i < 10; i++) {
    ...
}

In this challenge, you will use a for loop to increment a variable through a range.

Input Format

You will be given two positive integers,  and  (), separated by a newline.

Output Format

For each integer  in the inclusive interval :

• If , then print the English representation of it in lowercase. That is "one" for , "two" for , and so on.
• Else if  and it is an even number, then print "even".
• Else if  and it is an odd number, then print "odd".

Note: 

Sample Input

8
11

Sample Output

eight
nine
even
odd

SOLUTION:

#include <iostream>
#include <cstdio>
using namespace std;
int main() {
    // Complete the code.
    int a , b;
    cin>>a>>b;
    switch(a){
        case 1:
        if (b>=1){
            printf("one\n");
            }       
        else 
        break;        
        case 2:
        if (b>=2){
            printf("two\n");
            }       
        else 
        break;
        case 3:
        if (b>=3){
            printf("three\n");
            }       
        else 
        break;
        case 4:
        if (b>=4){
            printf("four\n");
            }       
        else 
        break;
        case 5:
        if (b>=5){
            printf("five\n");
            }       
        else 
        break;
        case 6:
        if (b>=6){
            printf("six\n");
            }       
        else 
        break;
        case 7:
        if (b>=7){
            printf("seven\n");
            }       
        else 
        break;
        case 8:
        if (b>=8){
            printf("eight\n");
            }       
        else 
        break;
        case 9:
        if (b>=9){
            printf("nine\n");
            }       
        else 
        break;
    }
    
    for(a=10 ; a<=b ; a++){
        if (a%2==0){
            printf("even\n");
        }
        else{
            printf("odd\n");
        }
    }











    
    return 0;
}