Lonely Integer

 Given an array of integers, where all elements but one occur twice, find the unique element.

Example

The unique element is .

Function Description

Complete the lonelyinteger function in the editor below.

lonelyinteger has the following parameter(s):

  • int a[n]: an array of integers

Returns

  • int: the element that occurs only once

Input Format

The first line contains a single integer, , the number of integers in the array.
The second line contains  space-separated integers that describe the values in .

Constraints

  • It is guaranteed that  is an odd number and that there is one unique element.
  • , where .

#!/bin/python3

import math
import os
import random
import re
import sys

#
# Complete the 'lonelyinteger' function below.
#
# The function is expected to return an INTEGER.
# The function accepts INTEGER_ARRAY a as parameter.
#

def lonelyinteger(a):
    # Write your code here
    res=a[0]
    for i in a[1:]:
        res=int(i)^res
    return res

if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')

    n = int(input().strip())

    a = list(map(int, input().rstrip().split()))

    result = lonelyinteger(a)

    fptr.write(str(result) + '\n')

    fptr.close()

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