Sum of even & odd

 Problem Statement

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Write a program to input an integer N and print the sum of all its even digits and all its odd digits separately.

Digits Mean Numbers, Not The Places! If The Given Integer Is "13245", Even Digits Are 2 & 4, And Odd Digits Are 1, 3 & 5.
Input Format :
 The only line of input contains a single integer N.
Output Format :
Print first even sum and then odd sum separated by space.
Constraints
0 <= N <= 10^8
Sample Input 1:
1234
Sample Output 1:
6 4
Sample Input 2:
552245
Sample Output 2:
8 15
Explanation For Sample Input 2:
For the given input, the even digits are 2, 2, and 4, and if we take the sum of these digits, it will come out to be 8(2 + 2 + 4), and similarly, if we look at the odd digits, they are, 5, 5 and 5 which makes a sum of 15(5 + 5 + 5). Hence the answer would be, 8(evenSum) <single space> 15(oddSum)

#Your code goes here
n=input()

lst=list(n)
e=0
o=0
for val in lst:
	
	if int(val)%2==0:
		e+=int(val)
	else:
		o+=int(val)
        
print(e,end=' ')
print(o)

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